Question #19991

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Question #19991

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Answer 1 · 2015-10-02T19:12:40

An impulse of $50 N s$ $50Ns$ is needed to keep the gun in position

Explanation:

The gun fires 600 bullets per minute, which is the same as 10 bullets per second. Each bullet has mass $25 g$ $25g$ , which is equal to $0.025 k g$ $0.025kg$ . 10 bullets, each of mass $0.025 k g$ $0.025kg$ leaving the muzzle at $200 m / s$ $200 m//s$ have a momentum, $m v$ $mv$ of:
$\Rightarrow 10 \times 0.025 k g \times 200 m / s = 50 k g m / s$ $=>10xx0.025kgxx200m//s = 50 kg m//s$

The force required to change momentum is called impulse. It is the product of force and time, $F \times t$ $Fxxt$ , that is required to cause a change in momentum of $Deltamv$ . It is derived as shown:
$F=mxxa$
$=> F=mxx(Deltav//t)$
$therefore Fxxt =mxxDeltav$

Here, your value of $mv$ is $50kgm//s$ and hence your value of $Fxxt$ should be $50Ns$

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Question #19991

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