How do I prove that #1/(sec A+1)+1/(sec A-1)#=#2 csc A cot A# ?
1 Answer
Taking the Lowest common Multiple,
As you may be aware,
Simplifying,
Now
and
Substituting,
which can be written as
Now
Substituting, we get
Taking the Lowest common Multiple,
As you may be aware,
Simplifying,
Now
and
Substituting,
which can be written as
Now
Substituting, we get