How do you solve the identity $sin x + \sqrt{2} = - sin x$ $sin x + sqrt2 = - sin x$ ?

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How do you solve the identity $sin x + \sqrt{2} = - sin x$ $sin x + sqrt2 = - sin x$ ?

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Answer 1 · 2015-10-06T09:05:35

It is $sin x + \sqrt{2} = - sin x \Rightarrow 2 sin x = - \sqrt{2} \Rightarrow sin x = - \frac{\sqrt{2}}{2} \Rightarrow x = - \frac{π}{4} or x = - \frac{3 π}{4}$ $sin x + sqrt2 = - sin x=>2sinx=-sqrt2=>sinx=-sqrt2/2=> x=-pi/4 or x=-(3pi)/4$

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How do you solve the identity $sin x + \sqrt{2} = - sin x$ $sin x + sqrt2 = - sin x$ ?

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How do you solve the identity sin x + sqrt2 = - sin xsinx+√2=−sinxsin x + sqrt2 = - sin x?

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How do you solve the identity $sin x + \sqrt{2} = - sin x$ $sin x + sqrt2 = - sin x$ ?