How do you multiply #(3-y^6)(3-y^6)#?
1 Answer
Oct 10, 2015
Explanation:
Use the technique FOIL (First Outer Inner Last) to evaluate the multiplication.
First:
#3*3 = 9#
Outer:
#3* - y^6 = -3y^6#
Inner:
#-y^6 * 3 = -3y^6#
Last:
#y^6 *y^6 = y^12#
Now add all the products:
#9 -3y^6 - 3y^6 + y^12 = 9-6y^6 + y^12#
We reach our answer this way.
Hopefully this helped!