Question #6f7ed

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Answer 1 · 2015-10-15T21:48:06

Patricia - first "normalize" the data, then use a Standard Normal Table to find t.

$P (25.2 < x < t) = P [\frac{35.2 - 35.2}{4.7} < z < \frac{t - 35.2}{4.7}] = 0.148$ $P(25.2 < x < t) = P[(35.2-35.2)/4.7< z< (t-35.2)/4.7]= 0.148$

$= P [0 < z < \frac{t - 35.2}{4.7}] = 0.148$ $= P[0< z< (t-35.2)/4.7]= 0.148$

Now, look up in a Standard Normal Table the area under the curve from 0 to z such that the area is equal to 0.148.

z = 0.380

Now, solve for t:

$\frac{t - 35.2}{4.7} = 0.380$ $(t-35.2)/4.7 = 0.380$

$t = 37.0$ $t = 37.0$

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Hope that helped