How do you simplify $7sqrt108$ ?

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Answer 1 · 2015-10-17T11:40:11

$42sqrt3$

get the $sqrt108$

= $sqrt((9)(4)(3)$

$9$ and $4$ are perfect square

= $(3)(2)sqrt3$

= $6sqrt3$

then multiply $7$

= $(7)(6)sqrt3$

= $42sqrt3$

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