Question

What is the derivative of `y=ln[x/(2x+3)]^(1/2)`?

Answer 1

`y' = 3/(2x(2x+3))`

Explanation:

`y=ln[x/(2x+3)]^(1/2) = 1/2 ln[x/(2x+3)]`

`y'=1/2 * 1/(x/(2x+3)) * (2x+3-2x)/(2x+3)^2 = 3/(2x(2x+3))`