Question #5164f

1 Answer
Oct 18, 2015

#color(red)(alpha(117"°C")Omega)# more than Conductor A.

Explanation:

You can solve this by using the formula:

#R=R_0[1+alpha(T-T_0)]#

Where:
#R# is the new resistance
#R_0# is the initial resistance
#alpha# is the temperature coefficient
#T# is the new temperature
#T_0# is the initial temperature

Take a look at our given:
#R_0=0.36Omega#
#T=350"°C"#
#T_0=25"°C"#

Plug these values into the formula.

#[1]color(white)(XX)R=R_0[1+alpha(T-T_0)]#

#[2]color(white)(XX)R=(0.36Omega)[1+alpha(350"°C"-25"°C")]#

#[3]color(white)(XX)R=(0.36Omega)[1+alpha(325"°C")]#

#[4]color(white)(XX)R=(0.36Omega)+alpha(325"°C")(0.36Omega)#

#[5]color(white)(XX)color(red)(R=0.36Omega+alpha(117"°C")Omega)#

Since we don't know the temperature coefficient we can't compute for the actual resistance of Conductor B. However, you can say that the resistance of Conductor B is #color(red)(alpha(117"°C")Omega)# more than Conductor A.