Question

How do you integrate `int4x(x^2+3)^(-3) dx`?

Answer 1

`-1/(x^2+3)^2 + C`

Explanation:

`int4x(x^2+3)^(-3) dx = 2 int (x^2+3)^(-3) 2xdx =`

`= 2 int (x^2+3)^(-3) (x^2+3)'dx = 2 int (x^2+3)^(-3) d(x^2+3) =`

`= 2 (x^2+3)^-2/-2 +C = -1/(x^2+3)^2 + C`