How do you solve #x-(3/x) = -2#?

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Answer 1 · 2015-10-20T09:50:09

#color(blue)(x=-3)# or #color(red)(x=1)#

Firstly take LCM.

#(x^2-3)/x=-2#

#x^2-3=-2x#

#x^2+2x-3=0#

Now mid term break.

#x^2+(3-1)x-3=0#

#x^2+3x-x-3=0#

#x(x+3)-1(x+3)=0#

Taking common.

#(x+3)(x-1)=0#

So either, #color(blue)(x+3=0)# or #color(blue)(x=-3)# OR #color(red)(x-1=0)# or #color(red)(x=1)#.