Question

Is the derivative of `sin^3[x] 3sin^2[x] (cos^3[x])`?

Answer 1

Nope. See the explanation.

Explanation:

`f(x)=sin^3x`

`f'(x) = ((sinx)^3)' = 3(sinx)^2 * (sinx)' = 3(sinx)^2 * cosx`

`f'(x) = 3sin^2xcosx`