What is the probability that an individual heterozygous for a cleft chin (Cc) and an individual homozygous for a chin without a cleft (cc) will produce offspring that are homozygous recessive for a chin without a cleft (cc)?
1 Answer
Oct 25, 2015
1/2
Explanation:
Here the parental genotype are : Cc and cc
The genes are therefore : C c c c
Hence, if you draw a punnet's square, it would appear like this
C | c
c|Cc cc
c|Cc cc
Hence it stands that Cc : cc =2:2
Thus the probability is 1/2