How do you write #(125)^(1/3)# in radical form?

1 Answer
Oct 26, 2015

#root(3)(125)#

Explanation:

Basically, a square root (#sqrt()#) is a number, say #x# raised to the power of #1/2#.

So if I have #sqrtx#, it is the same as saying if have #x^(1/2)#.

When the exponent is in fractions, the numerator just tells me how many times the power is, the denominator tells me the root. If the question here were #(125)^(2/3)#, then I would have #root(3)(125^2)#.

Now for your question. #(125)^(1/3)# is the same as #root(3)(125^1)#,
which evaluates to #5#, because #5xx5xx5=125#.