How do you differentiate $f (x) = - 3 tan 4 x^{2}$ $f(x)=-3tan4x^2$ using the chain rule?

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Answer 1 · 2015-10-28T06:59:04

$f'(x)=-24xsec^2(4x^2)$

Pull the constant out front

$f(x)=-3*tan(4x^2)$

Take the derivative of the outside, $tan$

$-3f'(x)=-3*sec^2(4x^2)$

Multiply the outside by the derivative of the inside, $4x^2$

$f'(x)=-3*sec^2(4x^2)(8x)$

$f'(x)=(-3)sec^2(4x^2)(8x)$

Simplify

$f'(x)=-24xsec^2(4x^2)$

How do you differentiate f(x)=-3tan4x^2f(x)=−3tan4x2f(x)=-3tan4x^2 using the chain rule?