How do you differentiate #f(x)=-3tan4x^2# using the chain rule?

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Answer 1 · 2015-10-28T06:59:04

#f'(x)=-24xsec^2(4x^2)#

Pull the constant out front

#f(x)=-3*tan(4x^2)#

Take the derivative of the outside, #tan#

#-3f'(x)=-3*sec^2(4x^2)#

Multiply the outside by the derivative of the inside, #4x^2#

#f'(x)=-3*sec^2(4x^2)(8x)#

#f'(x)=(-3)sec^2(4x^2)(8x)#

Simplify

#f'(x)=-24xsec^2(4x^2)#