Question

What is the vertex of `y = x^2 − 4x + 3`?

Answer 1

`(2,-1)`

Explanation:

First, find the axis of symmetry of the equation using `x=(-b)/(2a)`, where the values of `a` and `b` comes from `y=ax^2+bx+c`

In this case, `b = -4` and `a=1`.

So the axis of symmetry is `x=[-(-4)]/[(2)(1)]`
`x=2`

Then substitute the `x` value into the equation to find the `y` co-ordinate.

`y=(2)^2-4(2)+3`
`=4-8+3`
`=-1`

So the co-ordinates of the vertex are `(2,-1)`