What is the vertex of $y = x^2 − 4x + 3$ ?

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Answer 1 · 2015-10-30T10:40:24

$(2,-1)$

First, find the axis of symmetry of the equation using $x=(-b)/(2a)$ , where the values of $a$ and $b$ comes from $y=ax^2+bx+c$

In this case, $b = -4$ and $a=1$ .

So the axis of symmetry is $x=[-(-4)]/[(2)(1)]$
$x=2$

Then substitute the $x$ value into the equation to find the $y$ co-ordinate.

$y=(2)^2-4(2)+3$
$=4-8+3$
$=-1$

So the co-ordinates of the vertex are $(2,-1)$

What is the vertex of y = x^2 − 4x + 3y = x^2 − 4x + 3?