How do you simplify #5sqrt3/sqrt12#?

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Answer 1 · 2015-11-01T04:22:28

#5/2#

#[1]" "(5sqrt3)/sqrt12#

Rationalize the denominator by multiplying to #sqrt12/sqrt12#.

#[2]" "=(5sqrt3)/sqrt12*sqrt12/sqrt12#

#[3]" "=(5sqrt36)/12#

Get the principal square root of #36#.

#[4]" "=(5(6))/12#

#[5]" "=30/12#

Put in simplest terms.

#[6]" "=color(blue)(5/2)#