Question

How do you graph using the intercepts for `x-y=11`?

Answer 1

First, you would find the `x` and `y` intercepts for the line. Then, you would connect a line through them.

The `y`-intercept is `(0,-11)`
The `x`-intercept is `(11,0)`
graph{x-11 [-10, 10, -5, 5]}

Explanation:

To find the `y`-intercept: make `x=0` and solve for `y`. Your intercept is a point of the form `(0,y)`.

To find the `x`-intercept: make `y=0` and solve for `x`. Your intercept is a point of the form `(x,0)`.

We have the equation `x-y=11`

For the `y`-intercept, let's set `x=0` and solve for `y`:
`0-y=11`
`-y=11`
`y=-11`
So the `y`-intercept is `(0,-11)`

For the `x`-intercept, let's set `y=0` and solve for `x`:
`x-0=11`
`x=11`
So the `x`-intercept is `(11,0)`

Now, you just plot these two on an `x-y` plane and connect a straight line through them:

graph{x-11 [-10, 10, -5, 5]}