A rock in a sling is swung around in a circle. How would the centripetal force change if the rock was 9 times lighter?

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A rock in a sling is swung around in a circle. How would the centripetal force change if the rock was 9 times lighter?

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Answer 1 · 2015-11-04T20:46:47

The force would be $\frac{1}{9} t h$ $1/9th$ of that required to spin the larger rock at the same speed.

Explanation:

The force required for angular acceleration is proportional to the mass and the rate of acceleration.
$F = m a$ $F = ma$
In this case we usually know either an angular speed ( $ω$ $omega$ ) or an instantaneous velocity ( $v$ $v$ ) and a radius ( $r$ $r$ ). So it's also correct to write either of these forms:
$F = m \frac{v^{2}}{r}$ $F=mv^2/r$
$F = m r ω^{2}$ $F=mromega^2$

In either case the force required changes in direct proportion to the mass. If $m = 9$ $m=9$ the force would be nine times larger than the case where $m = 1$ $m=1$ .

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A rock in a sling is swung around in a circle. How would the centripetal force change if the rock was 9 times lighter?

1 Answer

Explanation:

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