How do you find domain and range for # f(x) = (x^2 - 16) / (x^2 - 25)#?

1 Answer
Nov 5, 2015

Domain = #x in RR: x!=-5, 5#
Range = #x in RR: x!=1#

Explanation:

First solve for domain which for inverse functions is equal to all real numbers except for when the denominator is equal to zero (so solve #x^2-25=0 rarr x=-5,5# so the domain is equal to all real numbers except -5 and 5
To solve for range I had to graph it using (https://www.desmos.com/calculator), there is a mechanical way to find it but graphing is much easier and most of the time you should have access to a graphing calculator