Question

What is the amplitude, period and the phase shift of `y=- 2/3 sin πx`?

Answer 1

Amplitude: `2/3`
Period: `2`
Phase shift: `0^\circ`

Explanation:

A wave function of the form `y=A*sin(\omega x + \theta)` or `y=A*cos(\omega x + \theta)` has three parts:

1. `A` is the amplitude of the wave function. It does not matter if the wave function has a negative sign, amplitude is always positive.

2. `\omega` is the angular frequency in radians.

3. `theta` is the phase shift of the wave.

All you have to do is identify these three parts and you're almost done! But before that, you need to transform your angular frequency `omega` to the period `T`.

`T=\frac{2pi}{omega}=\frac{2pi}{pi}=2`