Question

How do you solve `-4x+8<1/2x +3`?

Answer 1

• Multiply by `2` to get rid of denominators and isolate the `x`'s
• Divide by the coifficient of x on both sides
  `x > 10/9`

Explanation:

Start off by multiplying by `2` to get rid of denominators
`-4x + 8 < 1/2x + 3 to -8x + 16 < x + 6`
NOTE: We are multiplying by `2` since `2` is the highest common denominator.

Isolate the x's:
`-8x - x < 6 - 16`

..add
`-9x < -10`

Divide by -9. NOTE: Turn the "is larger than" sign when you are dividing (or multiplying) by a negative number.

`(-9x)/-9 > -10/-9 to (cancel(-9)x)/(cancel(-9)) > (-10)/-9 to x > 10/9`