How do you solve -4x+8<1/2x +3−4x+8<12x+3?

1 Answer
Eivind K.
Nov 7, 2015
  • Multiply by 22 to get rid of denominators and isolate the xx's
  • Divide by the coifficient of x on both sides
    x > 10/9x>109

Explanation:

Start off by multiplying by 22 to get rid of denominators
-4x + 8 < 1/2x + 3 to -8x + 16 < x + 6−4x+8<12x+3→−8x+16<x+6
NOTE: We are multiplying by 22 since 22 is the highest common denominator.

Isolate the x's:
-8x - x < 6 - 16−8x−x<6−16

..add
-9x < -10−9x<−10

Divide by -9. NOTE: Turn the "is larger than" sign when you are dividing (or multiplying) by a negative number.

(-9x)/-9 > -10/-9 to (cancel(-9)x)/(cancel(-9)) > (-10)/-9 to x > 10/9

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