A solid rubber stopper has a mass of $33.0$ $33.0$ grams and a volume of $30.0$ $30.0$ $c m^{3}$ $cm^3$ . What is the density of rubber?

Question

8542 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-09T23:11:30

$1.1 \frac{g}{c m^{3}}$ $1.1g/(cm^3)$

Density is $\frac{m a s s}{v o l u m e}$ $(mass)/(volume)$

Therefore the equation would look like

$\frac{33.0 g}{30.0 c m^{3}}$ $(33.0g)/(30.0cm^3)$ = $1.1 \frac{g}{c m^{3}}$ $1.1(g)/(cm^3)$

A solid rubber stopper has a mass of 33.033.033.0 grams and a volume of 30.030.030.0 cm^3cm3cm^3. What is the density of rubber?