For what r does #3/(n^(2r - 3))# converge or diverge?

1 Answer
Nov 10, 2015

For #r>=3/2# and only for them.

Explanation:

Let #alpha# be a real number.
The sequence #(1/n^alpha)_(n \in NN^*)# converges if and only if #alpha >= 0#.

Of course, #(1/n^alpha)_(n \in NN^*)# converges iff #(3/n^alpha)_(n \in NN^*)# converges...

So, here, the sequence converges iff #2r-3>=0# iff #r>=3/2#.