What is the z-score of sample X, if $n = 54, μ = 37, S t . D e v . = 30, and μ_{X} = 42$ $n = 54, mu= 37, St. Dev. =30, and mu_X =42$ ?

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What is the z-score of sample X, if $n = 54, μ = 37, S t . D e v . = 30, and μ_{X} = 42$ $n = 54, mu= 37, St. Dev. =30, and mu_X =42$ ?

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Answer 1 · 2015-11-10T10:22:25

$z = 1.225$ $z=1.225$

Explanation:

$μ_{x}$ $mu_x$ represents one of the value of the distribution.
$μ_{¯ x} = μ$ $mu_barx=mu$
We have to find the Standard Error of the given distribution.

It is - SD $= \frac{σ}{\sqrt{n}} = \frac{30}{\sqrt{54}} = \frac{30}{7.35} = 4.08$ $= sigma/sqrtn= 30/sqrt 54=30/7.35=4.08$

$z = \frac{μ_{x} - μ}{σ} = \frac{42 - 37}{4.08} = 1.225$ $z=(mu_x-mu)/sigma=(42-37)/4.08=1.225$

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What is the z-score of sample X, if $n = 54, μ = 37, S t . D e v . = 30, and μ_{X} = 42$ $n = 54, mu= 37, St. Dev. =30, and mu_X =42$ ?

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What is the z-score of sample X, if n = 54, mu= 37, St. Dev. =30, and mu_X =42n=54,μ=37,St.Dev.=30,andμX=42n = 54, mu= 37, St. Dev. =30, and mu_X =42?

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Explanation:

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What is the z-score of sample X, if $n = 54, μ = 37, S t . D e v . = 30, and μ_{X} = 42$ $n = 54, mu= 37, St. Dev. =30, and mu_X =42$ ?