How do you solve $4 - (2 x - 9) = - 19$ $4 - (2x - 9)= -19$ ?

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Answer 1 · 2015-11-12T23:26:31

By going through the problem like an equation getting $x$ $x$ by itself.

I'm just going to go step by step explaining each step.

$4 - (2 x - 9) = - 19$ $4-(2x-9)=-19$ is our original equation.

Now I'm going to get rid of the parenthesis by distributing the negative outside of it.

$4 - 2 x + 9 = - 19$ $4-2x+9=-19$

Now I'm going to gather like terms.

$13 - 2 x = - 19$ $13-2x=-19$

Now I'm going to get $2 x$ $2x$ by itself so we can solve for $x$ $x$ by subtracting $13$ $13$ from each side.

$- 2 x = - 32$ $-2x = -32$

Now I'm going to divide each side by $- 2$ $-2$ to get $x$ $x$ by itself, and that will get us our final answer.

$x = 16$ $x = 16$

How do you solve 4 - (2x - 9)= -194−(2x−9)=−194 - (2x - 9)= -19?