Given a right triangle ABC with right angle at C, if a is 4 and c is 8, what is b?

1 Answer

b=4 sqrt(3) approx 6.928b=436.928

Explanation:

Assuming that aa is the side opposed to the vertex AA, bb is the side opposed to the vertex BB and cc is the side opposed to the vertex CC, we have that the hypotenuse is c=8c=8 and a=4a=4 is one of the two legs.

Then you can use the Pythagorean Theorem as follows:
b=sqrt(c^2-a^2)=sqrt(8^2-4^2)=sqrt(64-16)=sqrt(48)=sqrt(16 * 3)=4 sqrt(3) approx 6.928b=c2a2=8242=6416=48=163=436.928