A rectangular solid has a surface area of $22 cm^2$ and a volume of $6 cm^3$ . What is the surface-area-to-volume ratio?

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Answer 1 · 2015-11-14T03:40:39

$3.667\text{cm}^{-1}$

The surface-area-to-volume ratio is simply the surface area divided by the volume of the object, and it has units of $L^{-1}$ ,called inverse lenght.

$\text{SA:V}=\frac{22\text{cm}^2}{6\text{cm}^3}=3.667\text{cm}^{-1}$

A rectangular solid has a surface area of 22 cm^222 cm^2 and a volume of 6 cm^36 cm^3. What is the surface-area-to-volume ratio?