What are the mean and standard deviation of a binomial probability distribution with #n=12 # and #p=5/37 #? Statistics Random Variables Mean and Standard Deviation of a Probability Distribution 1 Answer Gary M. · Clupeid Nov 18, 2015 #"Mean" = 12*5/37 = 60/37 = 1.62# #"Standard deviation" = (12*5/37*32/37)^(1/2) = 1.18# Explanation: #"Mean" = "n"*"p"# #"SD" = ("n"* "p"*"q") ^(1/2)# #"q" = 1-"p"# Answer link Related questions How do you calculate the standard deviation of a bounded probability distribution function? If the price of gasoline follows a normal distribution, has a mean of $2.30 per gallon, and a... Can a data set with two or three numbers have a standard deviation? Is the standard deviation of a data set invariant to translation? How can you use the standard deviation to calculate variance? What is Chebyshev's inequality? What is the standard deviation of just one number? What is the formula for the standard error? What is the standard error of: {50.6, 59.8, 50.9, 51.3, 51.5, 51.6, 51.8, 52.0}? If IQ scores are normally distributed with a mean of 100 and a standard deviation of 15, what... See all questions in Mean and Standard Deviation of a Probability Distribution Impact of this question 1618 views around the world You can reuse this answer Creative Commons License
