How do you factor the trinomial $x^{2} - 5 x y - 6 y^{2}$ $x^2-5xy-6y^2$ ?

Question

How do you factor the trinomial $x^{2} - 5 x y - 6 y^{2}$ $x^2-5xy-6y^2$ ?

1 Answer

Impact of this question

4034 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-18T16:17:45

$(x + y) (x - 6 y)$ $(x + y) (x - 6y)$

Explanation:

Hi. I don't know how to explain this. I just end up with that answer. :)

The general expression for factoring is that if the factors are $(x + a) \cdot (x + b)$ $(x+a)*(x+b)$ the trinomial is $x^{2} + (a + b) x + a b$ $x^2 +(a+b)x + ab$ . The addition of the second variable y does not invalidate this.
By inspection $a = - 6$ $a = -6$ and $b = 1$ $b = 1$

Science

Math

Humanities

... and beyond

How do you factor the trinomial $x^{2} - 5 x y - 6 y^{2}$ $x^2-5xy-6y^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor the trinomial x2−5xy−6y2x^2-5xy-6y^2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor the trinomial $x^{2} - 5 x y - 6 y^{2}$ $x^2-5xy-6y^2$ ?