What is the equation of the line passing through #(99,-40)# and #(104,-91)#?

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Answer 1 · 2015-11-19T12:54:31

#y = (-51x)/5 -15036/5#

Usung the formula #y-y_1 = m(x-x_1)#
Considering
#(99, -40) and (104, -91)#
#(x_1, y_1) and (x_2, y_2)#

m (gradient) = #(y_2-y_1)/(x_2-x_1)#

m = #(-91-(-40))/(104-99)#

m = #-51/5#

#y-(-40) = -51/5(x-99)#

#y-(-40) = (-51x)/5+5049/5#

#y = (-51x)/5+5049/5-4017#

#y = (-51x)/5 -15036/5#

This is the equation of the line