What is the distance between (15,24)(15,24) and (42,4)(42,4)?

1 Answer
Johnson Z.
Nov 23, 2015

The distance between (15, 24)(15,24) and (42, 4)(42,4) is approximately 33.633.6 units.

Explanation:

The formula for the distance between 22 points is:

d=sqrt(((x_"2"-x_"1")^2+(y_"2"-y_"1")^2))d=√((x2−x1)2+(y2−y1)2)

1^(st)1st point: (x_"1",y_"1")(x1,y1) = (15, 24)(15,24)
2^(nd)2nd point: (x_"2",y_"2")(x2,y2) = (42, 4)(42,4)

Substitute the points into the distance formula:

d=sqrt(((x_"2"-x_"1")^2+(y_"2"-y_"1")^2))d=√((x2−x1)2+(y2−y1)2)
d=sqrt(((42)-(15))^2+((4)-(24))^2)d=√((42)−(15))2+((4)−(24))2
d=sqrt((27)^2+(-20)^2)d=√(27)2+(−20)2
d=sqrt((729)+(400)d=√(729)+(400)
d=sqrt(1129)d=√1129
d~~33.6d≈33.6

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