What are the mean and standard deviation of a binomial probability distribution with n=130 n=130 and p=3/4 p=34?
1 Answer
Nov 26, 2015
Mean is nxp and variance is nxpxq
Explanation:
Here n = 130
p =
3/434
q =1/414
So mean = 130 x(3/4)(34) =390 / 43904 = 97.5
Variance = 130 x3/434 x1/414 =390/1639016 = 24.375
Standard deviation =sqrt(variance)√variance =sqrt(24.375)√24.375