What is the equation of the line tangent to # f(x)=sqrt(e^x-x) # at # x=1#?
1 Answer
Nov 30, 2015
2y=
OR y=
Explanation:
f(x)= #sqrt(e^x-x)
First derivative at x=1 is the slope of the tangent to f(x) at x=1
f'(x)=
f'(1)=
f'(1) =
slope =
using equation of line in point slope form
y-y1=m(x-x1) ; m=slope=
y-
2y-2
2y=
y=