Question

What is the equation of a line that goes through the points `(-12, 3)` and `(8, 15)`?

Answer 1

the equation of a line passing through 2 points `(x_1,y_1),(x_2,y_2)` is given as:

`y-y_1=m(x-x_1)`

`and m=(y_2-y_1)/(x_2-x_1)` called the slope of the line

therefore putting the given points in the above equation we end up getting:

`m=(15-3)/(8-(-12))=12/20=3/5`

`y-3=(3/5)(x-(-12))`
`5y-15=3x+36`
`3x-5y+51=0`