What is the slope of any line perpendicular to the line passing through $(- 3, 4)$ $(-3,4)$ and $(- 2, 3)$ $(-2,3)$ ?

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Answer 1 · 2015-12-04T19:44:08

$1$ $1$

To find the slope of the line passing through $(- 3, 4)$ $(-3, 4)$ and $(- 2, 3)$ $(-2,3)$ , we can use the formula

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

which gives us

$m = \frac{4 - 3}{- 2 - (- 3)} = \frac{- 1}{1} = - 1$ $m = (4 - 3)/(-2 - (-3)) = (-1)/1 = -1$

To find the slope of the line perpendicular to this line we simply take the negative reciprocal of this slope:

$- \frac{1}{- 1} = 1$ $- 1/(-1) = 1$

What is the slope of any line perpendicular to the line passing through (−3,4)(-3,4) and (−2,3)(-2,3)?