How do you solve the inequality $\frac{2 (3 y + 6)}{5} < 5 y + \frac{1}{4}$ $(2(3y+6))/5<5y+1/4$ ?

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How do you solve the inequality $\frac{2 (3 y + 6)}{5} < 5 y + \frac{1}{4}$ $(2(3y+6))/5<5y+1/4$ ?

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Answer 1 · 2015-12-06T00:22:56

$y > \frac{43}{76}$ $y>43/76$

Explanation:

$2 \frac{3 y + 6}{5} < 5 y + \frac{1}{4}$ $2(3y+6)/5 < 5y+1/4$

$\frac{6 y}{5} + \frac{12}{5} < 5 y + \frac{1}{4}$ $(6y)/5 + 12/5 < 5y+1/4$

$5 (\frac{6 y}{5} + \frac{12}{5}) < (5 y + \frac{1}{4}) 5$ $5((6y)/5 + 12/5) < (5y+1/4)5$

$6 y + 12 < 25 y + \frac{5}{4}$ $6y+12<25y+5/4$

$12 < 19 y + \frac{5}{4}$ $12<19y+5/4$

$(12) 4 < (19 y + \frac{5}{4}) 4$ $(12)4<(19y+5/4)4$

$48 < 76 y + 5$ $48<76y+5$

$43 < 76 y$ $43<76y$

$y > \frac{43}{76}$ $y>43/76$

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How do you solve the inequality $\frac{2 (3 y + 6)}{5} < 5 y + \frac{1}{4}$ $(2(3y+6))/5<5y+1/4$ ?

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Explanation:

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