Question

How do you convert 9.45 moles g of `Al_2O_3` into grams of `Al_2O_3`?

Answer 1

`963.9g`

Explanation:

consider the relationship between the number of moles, molar mass and the mass of a compound,

`n= m/M`

where n is the number of moles, m is the mass of the compound and M is the molar mass of the compound.

you just have to multiply the number of moles (9.45 moles) by the molar mass of `Al_"2"O_"3"` which is `27*2+16*3 = 102`

so,
`m = 9.45 mol * 102gmol ^"-1"`

`m = 963.9g`