How do you find the asymptotes for #(x^3-x)/(x^3-4x)#?
1 Answer
Horizontal asymptote:
Vertical asymptote:
Discontinuity at
Explanation:
Given
Let's start by factoring the function
If you notice, there is a same factor of
Discontinuity aka hole on the graph at
Discontinuity at #(0, 1/4)
Horizontal asymptote :
Since degree and coefficient of the numerator and denominator are the same, hence the horizontal asymptote is
Vertical asymptote
Set the denominator of the reduce function equal to zero
graph{(x^3-x)/(x^3-4x) [-7.024, 7.024, -3.51, 3.51]}