What is the standard form of $y = (4 x + 3) (3 x + 4)$ $y=(4x + 3)(3x+4)$ ?

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What is the standard form of $y = (4 x + 3) (3 x + 4)$ $y=(4x + 3)(3x+4)$ ?

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Answer 1 · 2015-12-12T13:47:26

$y = 12 x^{2} + 25 x + 12$ $y=12x^2+25x+12$

Explanation:

To rewrite the equation in standard form, expand the brackets.

$y = (4 x$ $y=(color(red)(4x)$ $+ 3) (3 x$ $color(green)(+3))(color(orange)(3x)$ $+ 4)$ $color(blue)(+4))$

$y = 4 x (3 x)$ $y=color(red)(4x)(color(orange)(3x))$ $+ 4 x (4)$ $color(red)(+4x)(color(blue)(4))$ $+ 3 (3 x)$ $color(green)(+3)(color(orange)(3x))$ $+ 3 (4)$ $color(green)(+3)(color(blue)(4))$

Simplify.

$y = 12 x^{2} + 16 x + 9 x + 12$ $y=12x^2+16x+9x+12$

$y = 12 x^{2} + 25 x + 12$ $y=12x^2+25x+12$

Answer 2 · 2015-12-12T15:20:11

$A slightly different way of thinking about the method.$ $color(blue)("A slightly different way of thinking about the method.")$

$12 x^{2} + 25 x + 12$ $12x^2+25x+12$

Explanation:

Given: $(4 x + 3) (3 x + 4)$ $color(blue)((4x+3)color(red)((3x+4))$

Using the Distributive property

$4 x (3 x + 4) + 3 (3 x + 4)$ $color(blue)(4xcolor(red)((3x+4))+3color(red)((3x+4)))$

$(12 x^{2} + 16 x) + (9 x + 12)$ $(12x^2 +16x) +(9x+12)$

As there is no multiplication left to do we can 'get rid' of the brackets

$12 x^{2} + 16 x + 9 x + 12$ $12x^2 +16x +9x+12$

$12 x^{2} + 25 x + 12$ $12x^2+25x+12$

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What is the standard form of $y = (4 x + 3) (3 x + 4)$ $y=(4x + 3)(3x+4)$ ?

2 Answers

Explanation:

Explanation:

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What is the standard form of y=(4x + 3)(3x+4) y=(4x+3)(3x+4)y=(4x + 3)(3x+4) ?

2 Answers

Explanation:

Explanation:

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What is the standard form of $y = (4 x + 3) (3 x + 4)$ $y=(4x + 3)(3x+4)$ ?