How do you differentiate # f(x)= [(2x+3)/(x-2)][(5x-1)/(3x-2)] # using the chain rule.?
1 Answer
Dec 14, 2015
Derivative :
Explanation:
First, expand the function and combined like terms
#=(10x^2 +13x-3)/(3x^2 -8x+4)#
We can differentiate this using quotient rule
Let
#f'(x) = 20x+13#
Let
#g'(x) = 6x-8 #
#h'(x) = ((60x^3-121x^2-24x+52)-(60x^3- 2x^2-122x+24))/(3x^2-8x+4)^2#
#h'(x) = (60x^3 - 121x^2 -24x+52-60x^3+2x^2+122x-24)/(3x^2-8x+4)^2#
#h'(x) = (-119x^2 +98x+28)/(3x^2-8x+4)^2#