How do you find the asymptotes for #g(x) =( 3x^2)/(x^2 - 9)#?

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Answer 1 · 2015-12-14T21:10:57

Vertical asymptote: #x= -3, x= 3#

Horizontal asymptote: #y= 1#

Oblique/Slant- None

#g(x) = (3x^2)/(x^2-9)#

Vertical asymptote- set the denominator to zero
#x^2 - 9 =0#

#=> (x-3)(x+3)=0 #

#=>x+3 = 0 => x= -3#

#=>x-3= 0 => x= 3#

Horizontal asymptote- Degree of numerator and denominator are the SAME- then horizontal asymptote is

#y= 1#

No oblique/slant asymptote