How do you find the slope and intercept of $-3x-8y+6=0$ ?

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Answer 1 · 2015-12-15T04:22:25

Slope-Intercept Form:
$y=mx+b$
Where $m$ is the slope and $b$ is the y-intercept.

Original Equation:
$-3x-8y+6=0$

To put an equation into slope-intercept form, you have to isolate $y$ . This means you have to get $y$ by itself:

$-3x-8y+6=0$

$-3x-8y=-6$

$-8y=3x-6$

$y=(3x-6)/(-8)$

$y=(-3/8)x+(3/4)$

Once you have $y$ by itself, all you have to do is determine which number is your slope and which is your intercept.

You should end up with:
$m$ (slope) $=(-3/8)$
and
$b$ (y-intercept) $=(3/4)$

How do you find the slope and intercept of -3x-8y+6=0-3x-8y+6=0?