How do you normalize # <3,1,5>#?

1 Answer
101
Dec 15, 2015

#<3/sqrt35,1/sqrt35,5/sqrt35>#

Explanation:

First, you have to calculate for the magnitude of the vector .

#||v||=sqrt(3^2+1^2+5^2)=sqrt35#

Second, divide the magnitude by each of the component of the vector.

#1/sqrt35 <3,1,5> = <3/sqrt35,1/sqrt35,5/sqrt35>#

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