How do you normalize $< 3, 1, 5 >$ $<3,1,5>$ ?

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How do you normalize $< 3, 1, 5 >$ $<3,1,5>$ ?

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Answer 1 · 2015-12-15T15:16:24

$< \frac{3}{\sqrt{35}}, \frac{1}{\sqrt{35}}, \frac{5}{\sqrt{35}} >$ $<3/sqrt35,1/sqrt35,5/sqrt35>$

Explanation:

First, you have to calculate for the magnitude of the vector .

$| | v | | = \sqrt{3^{2} + 1^{2} + 5^{2}} = \sqrt{35}$ $||v||=sqrt(3^2+1^2+5^2)=sqrt35$

Second, divide the magnitude by each of the component of the vector.

$\frac{1}{\sqrt{35}} < 3, 1, 5 > = < \frac{3}{\sqrt{35}}, \frac{1}{\sqrt{35}}, \frac{5}{\sqrt{35}} >$ $1/sqrt35 <3,1,5> = <3/sqrt35,1/sqrt35,5/sqrt35>$

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How do you normalize $< 3, 1, 5 >$ $<3,1,5>$ ?

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