How do you solve $3 x (x - 5) = 7 x^{2} - 16 x$ $3x(x - 5) = 7x^2 - 16x$ ?

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Answer 1 · 2015-12-17T07:26:09

Distribute in the left side and solve the resulting quadratic equation.

3x(x - 5) = $7 x^{2}$ $7x^2$ - 16x

$3 x^{2}$ $3x^2$ - 15x = $7 x^{2}$ $7x^2$ - 16x

0 = $4 x^{2}$ $4x^2$ - x

You can now solve by factoring:

0 = x(4x - 1)

x = 0 and $\frac{1}{4}$ $1/4$ .

Your solution set is x = 0 and x = $\frac{1}{4}$ $1/4$ .

Hopefully you understand.

How do you solve 3x(x−5)=7x2−16x3x(x - 5) = 7x^2 - 16x?