Question

How do you find the zeros of `y = 7x^2 + x -2` using the quadratic formula?

Answer 1

The roots are `(-1 +- sqrt(57))/14`.

Explanation:

You first calculate `Delta = b^2 - 4ac`, which here equals to `1 - 4*7*(-2) = 57`. It's positive so `y` has two roots.

The quadratic formula says that the roots of a trinomial are `(-b +- sqrt(Delta))/(2a`. So the two roots of `y` are `(-1 - sqrt(57))/14` and `(-1 + sqrt(57))/14`.