Question #dce15

1 Answer
Dec 22, 2015

This identity is false, AKA not an identity.

Explanation:

To show that an equation isn't true, all you need is a counterexample.

Assume that #alpha = beta = pi/6#.

The left-hand side of the equation evaluates to #2#. However, the right-hand side evaluates to #(2sqrt(3))/3#. Since it doesn't hold for these particular values of #alpha# and #beta# it's reasonable to say that this equation is false in general.

Did you possibly make a typo? Typically if you're asked to prove something, it's actually true.