Question

What is the vertex of `y= x^2-2x-2`?

Answer 1

`(1,-3)`

Explanation:

Vertex `= (-b/(2a) , f(-b/(2a)))`

In your case,

`-b/(2a) = (- (-2))/2 = 1`

and

`f(1)=1^2 - 2(1) -2`

`=1-2-2`

`= -3`