What is the vertex of y= x^2-2x-2y=x2−2x−2?
1 Answer
Explanation:
Vertex
In your case,
-b/(2a) = (- (-2))/2 = 1−b2a=−(−2)2=1
and
f(1)=1^2 - 2(1) -2f(1)=12−2(1)−2
=1-2-2=1−2−2
= -3=−3
Vertex
In your case,
-b/(2a) = (- (-2))/2 = 1−b2a=−(−2)2=1
and
f(1)=1^2 - 2(1) -2f(1)=12−2(1)−2
=1-2-2=1−2−2
= -3=−3