How do you factor the trinomial #15m^2 + 19m + 6#?

1 Answer
Dec 23, 2015

#(m+2/3)*(m+3/5)#

Explanation:

first make sure the coefficient of #m^2# is 1
you can factorize a quadratic polynomial in the form:
#m^2+#(sum of two numbers)#m+#(product of two numbers)
let the two numbers be #a,b#
so, from the equation, we have
#a+b = 19/15# #&# #a*b = 6/15#

solve this 2 equation 2 unknown by substituting either #a=6/(15b)# or #b=6/(15a)# into the eq #a+b=19/15#
on solving you get the two numbers #a# & #b# as #2/3,3/5#
now, you can write:
#m^2+(2/3+3/5)m+(2/3*3/5)#
#m^2+2/3m+3/5m+(2/3*3/5)#
#m(m+2/3)+3/5(m+2/3)#
#(m+2/3)*(m+3/5)#