How do you factor the trinomial $x^{2} + 8 x - 48$ $x^2 + 8x - 48$ ?

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How do you factor the trinomial $x^{2} + 8 x - 48$ $x^2 + 8x - 48$ ?

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Answer 1 · 2015-12-23T09:42:47

$(x + 12) (x - 4)$ $(x+12)(x-4)$

Explanation:

Just think of two real numbers that gives a product of $- 48$ $-48$ and a sum of $8$ $8$ , which is $12$ $12$ and $- 4$ $-4$
So the factored form of $x^{2} + 8 x - 48$ $x^2+8x-48$ is $(x + 12) (x - 4)$ $(x+12)(x-4)$

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How do you factor the trinomial $x^{2} + 8 x - 48$ $x^2 + 8x - 48$ ?

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How do you factor the trinomial x2+8x−48x^2 + 8x - 48?

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How do you factor the trinomial $x^{2} + 8 x - 48$ $x^2 + 8x - 48$ ?