Question

What is the equation of the line that passes through `(-1,7)` and is perpendicular to the line that passes through the following points: `(1,3),(-2,6)`?

Answer 1

`y=x+8`

Explanation:

The equation of line passing through (-1,7) is `y-7 = m *(x+1)` where m is the slope of the line.
The slope of the other perpendicular line, `m1 = (6-3)/(-2-1) = -1`
Condition of perpendicularity is `m*m1 = -1` so the slope `m = 1`
Thus the equation of the line is `y-7 = 1 * (x+1`) or `y= x+8` (Answer)