What is the equation of the line that passes through #(-1,7)# and is perpendicular to the line that passes through the following points: #(1,3),(-2,6) #?

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What is the equation of the line that passes through #(-1,7)# and is perpendicular to the line that passes through the following points: #(1,3),(-2,6) #?

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Answer 1 · 2015-12-24T10:50:29

#y=x+8#

Explanation:

The equation of line passing through (-1,7) is #y-7 = m *(x+1)# where m is the slope of the line.
The slope of the other perpendicular line, #m1 = (6-3)/(-2-1) = -1#
Condition of perpendicularity is #m*m1 = -1# so the slope #m = 1#
Thus the equation of the line is #y-7 = 1 * (x+1#) or #y= x+8# (Answer)

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What is the equation of the line that passes through #(-1,7)# and is perpendicular to the line that passes through the following points: #(1,3),(-2,6) #?

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